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Evaluate ∫∫x2+y2 dxdy in the positive quadrant for which x+y<=1.

Posted: Thu Jul 14, 2022 9:41 am
by answerhappygod
a) \(\frac{1}{2} \)
b) \(\frac{1}{3} \)
c) \(\frac{1}{6} \)
d) \(\frac{1}{12} \)