Find the inverse of the matrix by using Cayley Hamilton Theorem. A = \( ~ \begin{bmatrix} 1 & 0 & 0\\ 0 & 1 & 1\\ 0 & -2
Posted: Thu Jul 14, 2022 9:41 am
a) \(\frac{1}{6} \begin{bmatrix}
1 & 0 & 0\\
0 & -1 & -1\\
0 & 2 & -4\\
\end{bmatrix} \)
b) \(\frac{1}{6} \begin{bmatrix}
1 & 0 & 0\\
0 & 1 & 1\\
0 & 2 & 4\\
\end{bmatrix} \)
c) \(\frac{1}{6} \begin{bmatrix}
1 & 0 & 0\\
0 & -1 & -1\\
0 & -2 & -4\\
\end{bmatrix} \)
d) \(\frac{1}{6} \begin{bmatrix}
1 & 0 & 0\\
0 & 1 & 1\\
0 & -2 & 4\\
\end{bmatrix} \)
1 & 0 & 0\\
0 & -1 & -1\\
0 & 2 & -4\\
\end{bmatrix} \)
b) \(\frac{1}{6} \begin{bmatrix}
1 & 0 & 0\\
0 & 1 & 1\\
0 & 2 & 4\\
\end{bmatrix} \)
c) \(\frac{1}{6} \begin{bmatrix}
1 & 0 & 0\\
0 & -1 & -1\\
0 & -2 & -4\\
\end{bmatrix} \)
d) \(\frac{1}{6} \begin{bmatrix}
1 & 0 & 0\\
0 & 1 & 1\\
0 & -2 & 4\\
\end{bmatrix} \)