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Find the inverse lapace of \(\frac{(s+1)}{[(s+1)^2+4][(s+1)^2+1]}\).

Posted: Thu Jul 14, 2022 9:41 am
by answerhappygod
a) 1⁄3 et [Cos(t) – Cos(2t)].
b) 1⁄3 e-t [Cos(t) + Cos(2t)].
c) 1⁄3 et [Cos(t) + Cos(2t)].
d) 1⁄3 e-t [Cos(t) – Cos(2t)].