What is the solution of D.E (D2 – 2D)y = ex sinx when solved using the method of undetermined coefficients?
Posted: Thu Jul 14, 2022 9:29 am
a) \( y = c_1 + c_2 \,e^{2x} – \frac{e^x (xsin x + cosx)}{2}\)
b) \(y = c_1 + c_2 \,e^{2x} – \frac{e^x sin x}{2}\)
c) \(y = c_1 + c_2 \,e^{2x} – \frac{e^x cos x}{2}\)
d) \(y = c_1 + c_2 \,e^{2x} – \frac{e^x (sin x + x cosx)}{4}\)
b) \(y = c_1 + c_2 \,e^{2x} – \frac{e^x sin x}{2}\)
c) \(y = c_1 + c_2 \,e^{2x} – \frac{e^x cos x}{2}\)
d) \(y = c_1 + c_2 \,e^{2x} – \frac{e^x (sin x + x cosx)}{4}\)