What is the solution of the given equation?
Posted: Thu Jul 14, 2022 9:29 am
x6y6 dy + (x7y5 +1) dx = 0
a) \(\frac{(xy)^6}{6} + lnx = c \)
b) \(\frac{(xy)^5}{6} + lny = c\)
c) \(\frac{(xy)^5}{5}+ lnx = c\)
d) \(\frac{(xy)^6}{6}+ lny = c\)
a) \(\frac{(xy)^6}{6} + lnx = c \)
b) \(\frac{(xy)^5}{6} + lny = c\)
c) \(\frac{(xy)^5}{5}+ lnx = c\)
d) \(\frac{(xy)^6}{6}+ lny = c\)