Solution of the differential equation \(\frac{dy}{dx} -y \,tanx = \frac{sinx cos^2x}{y^2}\) is ______
Posted: Thu Jul 14, 2022 9:29 am
a) \(y \,cos^2 x = \frac{-cos^4 xsin^2 x}{2} + c\)
b) \(y^2 cos^2 x = \frac{sin^6 x}{2} + c \)
c) \(y^3 cos^3 x = \frac{-cos^6 x}{2} + c \)
d) \(y^4 cos^5 x = \frac{sinx cosx}{2} + c \)
b) \(y^2 cos^2 x = \frac{sin^6 x}{2} + c \)
c) \(y^3 cos^3 x = \frac{-cos^6 x}{2} + c \)
d) \(y^4 cos^5 x = \frac{sinx cosx}{2} + c \)