Solution of the differential equation \(\frac{dy}{dx} = \frac{y-x+1}{y+x+5}\) is ______
Posted: Thu Jul 14, 2022 9:29 am
a) \(π-tan{-1} \frac{y+3}{x+2} – log\sqrt{(x+2)^2+(y+3)^2}=c\)
b) \(-tan{-1} \frac{y+3}{x+2} – log\sqrt{(x+2)^2+(y+3)^2}=c\)
c) \(tan{-1} \frac{y+3}{x+2} – log\sqrt{x+y+5}=c\)
d) \(-cot{-1} \frac{y+3}{x+2} – log\sqrt{x+y+5}=c\)
b) \(-tan{-1} \frac{y+3}{x+2} – log\sqrt{(x+2)^2+(y+3)^2}=c\)
c) \(tan{-1} \frac{y+3}{x+2} – log\sqrt{x+y+5}=c\)
d) \(-cot{-1} \frac{y+3}{x+2} – log\sqrt{x+y+5}=c\)