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Solution of the differential equation (x-y)dy=(x+y+1)dx is _____

Posted: Thu Jul 14, 2022 9:29 am
by answerhappygod
a) \( \sqrt{x^2+y^2} = e^{c tan^{-1}⁡\left(\frac{y+0.5}{x+0.5}\right)}\)
b) \((x^2+y^2)^1.5 = c cot^{-1} ⁡\left(\frac{y+0.5}{x+0.5}\right)\)
c) \((x^2+y^2)^2 = e^{c cot⁡⁡\left(\frac{y+0.5}{x+0.5}\right)}\)
d) \((x^2+y^2)^1 = c tan⁡\left(\frac{y+0.5}{x+0.5}\right)\)