Find the value of \(\int\int\frac{1}{16x^2+16x+10} \,dx\).
Posted: Thu Jul 14, 2022 9:29 am
a) \(\frac{1}{8} (x+\frac{1}{2})Sin^{-1} (x+\frac{1}{2})-\frac{1}{2} ln(1+(x+\frac{1}{2})^2)\)
b) \(\frac{1}{8} (x+\frac{1}{2})tan^{-1} (x+\frac{1}{2})-\frac{1}{16} ln(1+(x+\frac{1}{2})^2)\)
c) \((x+1/2) cos^{-1} (x+\frac{1}{2})-\frac{1}{16} ln(1+(x+\frac{1}{2})^2)\)
d) \(\frac{1}{8} (x+\frac{1}{2}) sec^{-1} (x+\frac{1}{2})-\frac{1}{16} ln(1+(x+\frac{1}{2})^2)\)
b) \(\frac{1}{8} (x+\frac{1}{2})tan^{-1} (x+\frac{1}{2})-\frac{1}{16} ln(1+(x+\frac{1}{2})^2)\)
c) \((x+1/2) cos^{-1} (x+\frac{1}{2})-\frac{1}{16} ln(1+(x+\frac{1}{2})^2)\)
d) \(\frac{1}{8} (x+\frac{1}{2}) sec^{-1} (x+\frac{1}{2})-\frac{1}{16} ln(1+(x+\frac{1}{2})^2)\)