a) 1⁄8 sin-1(x + 1⁄2)
b) 1⁄8 tan-1(x + 1⁄2)
c) 1⁄8 sec-1(x + 1⁄2)
d) 1⁄4 cos-1(x + 1⁄2)
Find the value of \(\int \frac{1}{16x^2+16x+10}dx\).
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answerhappygod
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Find the value of \(\int \frac{1}{16x^2+16x+10}dx\).
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