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Find the value of ∫tan-1⁡(x)dx.

Posted: Thu Jul 14, 2022 9:29 am
by answerhappygod
a) sec-1 (x) – 1⁄2 ln⁡(1 + x2)
b) xtan-1 (x) – 1⁄2 ln⁡(1 + x2)
c) xsec-1 (x) – 1⁄2 ln⁡(1 + x2)
d) tan-1 (x) – 1⁄2 ln⁡(1 + x2)