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If \(z=sin^{-1}\frac{x^3+y^3+z^3}{x+y+z}\) then, \(x\frac{∂z}{∂x}+y\frac{∂z}{∂y}\).

Posted: Thu Jul 14, 2022 9:29 am
by answerhappygod
a) 2 tan(z)
b) 2 cot(z)
c) tan(z)
d) cot(z)