Find the derivative of Tan(x) = Tan(y).
Posted: Thu Jul 14, 2022 9:29 am
a) \(\frac{1+x^2}{1+y^2}\)
b) \(\frac{1+y}{1+x^2}\)
c) \(\frac{1+y^2}{1+x^2}\)
d) \(\frac{1+y^2}{1+x}\)
b) \(\frac{1+y}{1+x^2}\)
c) \(\frac{1+y^2}{1+x^2}\)
d) \(\frac{1+y^2}{1+x}\)