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What is the derivative of \(\frac{3x^2}{(1-sinx)}\)?

Posted: Thu Jul 14, 2022 9:29 am
by answerhappygod
a) \(\frac{6xsinx-3x^2 cosx}{(1-sinx)^2} \)
b) \(\frac{6x}{1-sinx} \)
c) \(\frac{6xsinx-3x^2 cosx-6x}{(1-sinx)^2} \)
d) \(\frac{6xsinx-3cosx-6}{(1-sinx)^2} \)