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Find \(lt_{x\rightarrow 0}\frac{(3e^x-2e^{2x}-e^{3x})}{(e^x+e^{2x}-2e^{3x})}\)
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Find \(lt_{x\rightarrow 0}\frac{(3e^x-2e^{2x}-e^{3x})}{(e^x+e^{2x}-2e^{3x})}\)
Posted:
Thu Jul 14, 2022 9:29 am
by
answerhappygod
a) 3⁄2
b) 0
c) 4⁄3
d) –4⁄3