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Find \(lt_{x\rightarrow -101}(\frac{ln(x^2+20x+(x+101)^2(x^2+3))-ln(x^2+20x)}{x^2+202x+10201})\).

Posted: Thu Jul 14, 2022 9:29 am
by answerhappygod
a) 0
b) 1
c) ∞
d) \(=\frac{10204}{12221}\)