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Find \(lt_{n\rightarrow\infty}\frac{(1^a+2^a+…+(n-1)^a)}{n^{a+1}}\)
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Find \(lt_{n\rightarrow\infty}\frac{(1^a+2^a+…+(n-1)^a)}{n^{a+1}}\)
Posted:
Thu Jul 14, 2022 9:29 am
by
answerhappygod
a) 1
b) 1⁄a + 1
c) 0
d) Undefined