Find the solution of differential equation, dy⁄dx = xy + x2, if y = 1 at x = 0.
Posted: Thu Jul 14, 2022 9:29 am
a) \(1-\frac{x^2}{2!}+\frac{3x^4}{4!}-\frac{15x^6}{6!}+…\)
b) \(\frac{x}{1!}+\frac{3x^3}{4!}+\frac{15x^5}{6!}+…\)
c) \(\frac{x}{1!}-\frac{3x^3}{4!}+\frac{15x^5}{6!}-…\)
d) \(1+\frac{x^2}{2!}+\frac{3x^4}{4!}+\frac{15x^6}{6!}+..\)
b) \(\frac{x}{1!}+\frac{3x^3}{4!}+\frac{15x^5}{6!}+…\)
c) \(\frac{x}{1!}-\frac{3x^3}{4!}+\frac{15x^5}{6!}-…\)
d) \(1+\frac{x^2}{2!}+\frac{3x^4}{4!}+\frac{15x^6}{6!}+..\)