Let f(x)=\(x-\frac{x^3}{3^2.2!}+\frac{x^5}{5^2.4!}-\frac{x^7}{7^2.6!}+…\infty\). Find a point nearest to c such that f'(
Posted: Thu Jul 14, 2022 9:27 am
a) 1
b) 0
c) 2.3445 * 10-9
d) 458328.33 * 10-3
view answer
b) 0
c) 2.3445 * 10-9
d) 458328.33 * 10-3
view answer