Find the sum to n terms of the series whose nth term is n (n-2).
Posted: Wed Jul 13, 2022 8:10 pm
a) \(\frac{n(n-1)(2n+4)}{6}\)
b) \(\frac{n(n+1)(2n-5)}{6}\)
c) \(\frac{(n-2)(2n-5)}{3}\)
d) \(\frac{n(n+1)(2n-5)}{3}\)
b) \(\frac{n(n+1)(2n-5)}{6}\)
c) \(\frac{(n-2)(2n-5)}{3}\)
d) \(\frac{n(n+1)(2n-5)}{3}\)