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For what value of θ, 1 lies between the roots of the quadratic equation 3x2 – 3sinθ x – 2cos2θ = 0?

Posted: Wed Jul 13, 2022 8:10 pm
by answerhappygod
a) 2nπ + π/6 < θ < 2nπ + 5π/6
b) 2nπ + π/3 < θ < 2nπ + 5π/3
c) 2nπ + π/6 ≤ θ ≤ 2nπ + 5π/6
d) 2nπ + π/3 ≤ θ ≤ 2nπ + 5π/3