A particle starts moving from rest with an acceleration in a fixed direction. If its acceleration at time t be(a – bt2),
Posted: Wed Jul 13, 2022 8:09 pm
a) [v]max = 4a√a/3√b
b) [v]max = 2a√a/3√b
c) [v]max = 2a√a/3√b
d) [v]max = 4a√a/3√b
b) [v]max = 2a√a/3√b
c) [v]max = 2a√a/3√b
d) [v]max = 4a√a/3√b