Find the cartesian equation of the line which is passing through the point (-1, -8, 5) and parallel to the vector \(7\ha
Posted: Wed Jul 13, 2022 8:09 pm
a) \(\frac{x+1}{-1}=\frac{y+8}{-8}=\frac{z-5}{5}\)
b) \(\frac{x+1}{7}=\frac{y+8}{-3}=\frac{z-5}{-3}\)
c) \(\frac{x-7}{7}=\frac{y+8}{-3}=\frac{z-3}{-3}\)
d) \(\frac{x+1}{7}=\frac{y+8}{-8}=\frac{z+5}{3}\)
b) \(\frac{x+1}{7}=\frac{y+8}{-3}=\frac{z-5}{-3}\)
c) \(\frac{x-7}{7}=\frac{y+8}{-3}=\frac{z-3}{-3}\)
d) \(\frac{x+1}{7}=\frac{y+8}{-8}=\frac{z+5}{3}\)