What is the equation of the curve passing through (1, 0) of (y(dy/dx) + 2x)2 = (y2 + 2x2)[1 + (dy/dx)2]?
Posted: Wed Jul 13, 2022 8:08 pm
a) √2x±1/√2 = y/x + √(y2 + 2x2)/x2
b) √2x±1/2√2 = y/x + √(y2 + 2x2)/x2
c) √2x√2 = y/x + √(y2 + 2x2)/x2
d) √2x = y/x + √(y2 + 2x2)/x2
b) √2x±1/2√2 = y/x + √(y2 + 2x2)/x2
c) √2x√2 = y/x + √(y2 + 2x2)/x2
d) √2x = y/x + √(y2 + 2x2)/x2