What is the solution of (y(dy/dx) + 2x)2 = (y2 + 2x2)[1 + (dy/dx)2]?
Posted: Wed Jul 13, 2022 8:08 pm
a) cx±1/√2 = y/x + √(y2 – 2x2)/x2
b) cx±√2 = y/x + √(y2 + 2x2)/x2
c) cx±1/2√2 = y/x + √(y2 – 2x2)/x2
d) cx±1/√2 = y/x + √(y2 + 2x2)/x2
b) cx±√2 = y/x + √(y2 + 2x2)/x2
c) cx±1/2√2 = y/x + √(y2 – 2x2)/x2
d) cx±1/√2 = y/x + √(y2 + 2x2)/x2