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Find \(\int_1^2\sqrt{x}-3x \,dx\).

Posted: Wed Jul 13, 2022 8:08 pm
by answerhappygod
a) \(\frac{8\sqrt{2}-31}{6}\)
b) \(8\sqrt{2}-31\)
c) \(\frac{\sqrt{2}-31}{3}\)
d) \(\frac{8\sqrt{2}+31}{4}\)