Find \(\int \frac{(x+3)}{2x^2+6x+7} dx\).
Posted: Wed Jul 13, 2022 8:07 pm
a) \(\frac{1}{4} log(2x^2+6x+7) + \frac{3}{4} \left (\frac{1}{\sqrt{2}} tan^{-1}\frac{2x+3}{2\sqrt{2}}\right )+C\)
b) \(\frac{1}{4} log(2x^2+6x+7) – \frac{3}{4} (\frac{1}{\sqrt{2}} tan^{-1}\frac{2x+3}{2\sqrt{2}} )+C\)
c) \(log(2x^2+6x+7) + \left (tan^{-1}\frac{2x+3}{2√2}\right )+C\)
d) –\(log(2x^2+6x+7) – \frac{3}{4} \left (\frac{1}{√2} tan^{-1}\frac{2x+3}{2√2}\right )+C\)
b) \(\frac{1}{4} log(2x^2+6x+7) – \frac{3}{4} (\frac{1}{\sqrt{2}} tan^{-1}\frac{2x+3}{2\sqrt{2}} )+C\)
c) \(log(2x^2+6x+7) + \left (tan^{-1}\frac{2x+3}{2√2}\right )+C\)
d) –\(log(2x^2+6x+7) – \frac{3}{4} \left (\frac{1}{√2} tan^{-1}\frac{2x+3}{2√2}\right )+C\)