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Find ∫ 2 sin3⁡x+1 dx

Posted: Wed Jul 13, 2022 8:07 pm
by answerhappygod
a) \(\frac{3}{2}-\frac{cos⁡3x}{6}+x+C\)
b) –\(\frac{3}{2} cos⁡x+\frac{cos⁡3x}{6}+x+C\)
c) –\(\frac{3}{2} cos⁡x-\frac{cos⁡3x}{6}-x+C\)
d) –\(\frac{3}{2} cos⁡x+\frac{cos⁡3x}{6}+C\)