Find ∫ 2 sin3x+1 dx
Posted: Wed Jul 13, 2022 8:07 pm
a) \(\frac{3}{2}-\frac{cos3x}{6}+x+C\)
b) –\(\frac{3}{2} cosx+\frac{cos3x}{6}+x+C\)
c) –\(\frac{3}{2} cosx-\frac{cos3x}{6}-x+C\)
d) –\(\frac{3}{2} cosx+\frac{cos3x}{6}+C\)
b) –\(\frac{3}{2} cosx+\frac{cos3x}{6}+x+C\)
c) –\(\frac{3}{2} cosx-\frac{cos3x}{6}-x+C\)
d) –\(\frac{3}{2} cosx+\frac{cos3x}{6}+C\)