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Find \(\int \frac{e^{-cot^{-1}⁡x}}{1+x^2}\).

Posted: Wed Jul 13, 2022 8:07 pm
by answerhappygod
a) \(e^{-cot^{-1}⁡x}+C\)
b) \(e^{-2cot^{-1}⁡x}+C\)
c) \(e^{-tan^{-1}⁡x}+C\)
d) \(e^{-cot^1⁡2x}+C\)