Find the integral of \(3e^x+\frac{2(log x)}{3x}\).
Posted: Wed Jul 13, 2022 8:07 pm
a) \(3e^x+\frac{1}{3} (x)^2+C\)
b) \(e^x-\frac{8}{3} (logx)^2+C\)
c) \(3e^x-\frac{1}{3} (logx)^2+C\)
d) \(3e^x+\frac{1}{3} (logx)^2+C\)
b) \(e^x-\frac{8}{3} (logx)^2+C\)
c) \(3e^x-\frac{1}{3} (logx)^2+C\)
d) \(3e^x+\frac{1}{3} (logx)^2+C\)