Find \(\int \,7x^8-4e^{2x}-\frac{2}{x^2} \,dx\).
Posted: Wed Jul 13, 2022 8:07 pm
a) \(\frac{7x^4}{4}-2e^{2x}+\frac{2}{x}+C\)
b) \(\frac{7x^4}{4}+2e^{2x}+\frac{2}{x}+C\)
c) \(\frac{7x^4}{4}-2e^{2x} \frac{2}{x^2}+C\)
d) \(\frac{7x^4}{8}+2e^{2x}-\frac{4}{x}+C\)
b) \(\frac{7x^4}{4}+2e^{2x}+\frac{2}{x}+C\)
c) \(\frac{7x^4}{4}-2e^{2x} \frac{2}{x^2}+C\)
d) \(\frac{7x^4}{8}+2e^{2x}-\frac{4}{x}+C\)