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If \(y = tan^{-1}(\frac{3x-x^3}{1-3x^2}), \frac{-1}{\sqrt{3}} < x < \frac{-1}{\sqrt{3}}\)

Posted: Wed Jul 13, 2022 8:07 pm
by answerhappygod
a) 3
b) \(\frac{3}{1+x}\)
c) –\(\frac{3}{1+x^2}\)
d) \(\frac{3}{1+x^2}\)