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What is the output of the following code?

Posted: Wed Jul 13, 2022 7:40 pm
by answerhappygod
#include<stdio.h>
int get_min(int a, int b)
{
if(a<b)
return a;
return b;
}
int minimum_time_required(int reach[][4],int spent[][5], int *entry, int *exit, int n)
{
int t1[n], t2[n], i;
t1[0] = entry[0] + spent[0][0];
t2[0] = entry[1] + spent[1][0];
for(i = 1; i < n; i++)
{
t1 = get_min(t1[i-1]+spent[0], t2[i-1]+reach[1][i-1]+spent[0]);
t2 = get_min(t2[i-1]+spent[1], t1[i-1]+reach[0][i-1]+spent[1]);
}
return get_min(t1[n-1]+exit[0], t2[n-1]+exit[1]);
}
int main()
{
int time_to_reach[][4] = {{16, 10, 5, 12},
{12, 4, 17, 8}};
int time_spent[][5] = {{13, 5, 20, 19, 9},
{15, 10, 12, 16, 13}};
int entry_time[2] = {12, 9};
int exit_time[2] = {10, 13};
int num_of_stations = 5;
int ans = minimum_time_required(time_to_reach, time_spent,
entry_time, exit_time, num_of_stations);
printf("%d",ans);
return 0;
}
a) 62
b) 69
c) 75
d) 88