Find the solution of the given initial value problem: y(4)+2y′′′+y′′+8y′−12y=6sin(t)+80e−ty(0)=0,y′(0)=569,y′′(0)=52,y
Posted: Wed Jul 13, 2022 5:08 am
Find the solution of the given initial value problem: y(4)+2y′′′+y′′+8y′−12y=6sin(t)+80e−ty(0)=0,y′(0)=569,y′′(0)=52,y′′′(0)=−577.y(t)=521et+(6sin(t)−51)cos(t)−52sin(t)−4e−t