Answer Happy

Posted: **Wed Jul 13, 2022 5:08 am**

: Let Xn Yn 1 Te A Sequence Of Independent Zandom Vatiables Such That X1 0 And For Any N 2p Xn N 2nlog N 1 P Xn 1 (42.27 KiB) Viewed 15 times

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Let {XnYn=1∞ te a sequence of independent zandom vatiables such that X1=0 and for any n>2P(Xn=n)=2nlog(n)1, P(Xn=−n)=2nlog(n)1,P(Xn=0)=1−nlog(n)1,letSn=n1(Xn+X2+⋯+Xn) 2. Caloulate P(n→∞limSn=0)

Answer Happy

Let {Xn​Yn=1∞​ te a sequence of independent zandom vatiables such that X1​=0 and for any n>2P(Xn​=n)=2nlog(n)1​, P(Xn​=−

Let {Xn​Yn=1∞​ te a sequence of independent zandom vatiables such that X1​=0 and for any n>2P(Xn​=n)=2nlog(n)1​, P(Xn​=−

Let {XnYn=1∞ te a sequence of independent zandom vatiables such that X1=0 and for any n>2P(Xn=n)=2nlog(n)1, P(Xn=−

Let {XnYn=1∞ te a sequence of independent zandom vatiables such that X1=0 and for any n>2P(Xn=n)=2nlog(n)1, P(Xn=−