Find the center of gravity of the region in the first octant bounded by x+y+z=1
Posted: Wed Jul 13, 2022 5:07 am
Find the center of gravity of the region in the first octantbounded by x+y+z=1
Let G=(xˉ,yˉ,zˉ) be the center of gravity of an object. The coordinates of the G is given by, xˉ=∭VρdV∭VxρdV,yˉ=∭VρdV∭VyρdV,zˉ=∭VρdV∭VzρdV Where, ρ be the mass of unit volume. Find the center of gravity of the region in the first octant bounded by x+y+z=1.
Let G=(xˉ,yˉ,zˉ) be the center of gravity of an object. The coordinates of the G is given by, xˉ=∭VρdV∭VxρdV,yˉ=∭VρdV∭VyρdV,zˉ=∭VρdV∭VzρdV Where, ρ be the mass of unit volume. Find the center of gravity of the region in the first octant bounded by x+y+z=1.