Find the solution of the given initial value problem: y′′′+y′=sec(t),y(0)=6,y′(0)=3,y′′(0)=−4 y(t)=−tcos(t)+4cos(t)+3sin
Posted: Wed Jul 13, 2022 5:06 am
Find the solution of the given initial value problem: y′′′+y′=sec(t),y(0)=6,y′(0)=3,y′′(0)=−4 y(t)=−tcos(t)+4cos(t)+3sin(t)+ln(tan(t)+sec(t))+ln(cos(t))sin(t)+2