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(a) θ→0limθ2sin(4θ)sin(5θ)=θ→0limθsin(40)⋅44⋅θ→0limθsin(5θ)⋅55=4⋅5=20
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(a) θ→0limθ2sin(4θ)sin(5θ)=θ→0limθsin(40)⋅44⋅θ→0limθsin(5θ)⋅55=4⋅5=20
Posted:
Wed Jul 13, 2022 5:06 am
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(a) θ→0limθ2sin(4θ)sin(5θ)=θ→0limθsin(40)⋅44⋅θ→0limθsin(5θ)⋅55=4⋅5=20