Answer Happy

2. Gianni is letting it rip to test out his new skis. He is on a slope with a steady (flat, but sloped) incline of 35° up from the horizontal. He starts out at 3.00 m/s going mostly across the slope so he starts with a velocity across the slope of 2.94 m/s and down along the slope at 0.52 m/s. He has no acceleration across the slope, but his acceleration down the slope is g sine-that's g sin35°... which is free-flight acceleration g times sin 35°... which is (9.80 m/s²) x (sin35°), but just work the equations with g sine in them until you put in the numbers. a. Make a sketch showing Gianni at the start and then at 2.00 s and 4.00 s. Show a good choice of coordinates-NOT horizontal and vertical, but rather horizontal and across the slope and straight down the slope. Why those coordinates? Because it is almost always best to choose coordinates where one direction has zero acceleration (nice and easy) and all of the acceleration is in the other direction. b. Relate states 1 and 2 to calculate Ax, (across the slope) and Ay,,, (down the slope). c. Relate states 1 and 3 to calculate Ax, (across the slope) and Ay,, (down the slope). First calculate v and then relate states 2 and 3 to calculate Ax,,, (across d. the slope) and Ay,, (down the slope). Are the results of b, c, and d consistent? Show how. e. f. Show and label: states 1, 2 (more than halfway down), and 3; displacement arrows for and Ax, and vertical Ay, and Ay velocity "components" 192 A horizontal Ax and , and , and and v. Put in the data that is given or implied. You didn't forget to show your chosen coordinates, did you? And you put the acceleration next to each coordinate axis, rinight! g Without calculation, what is implied about v. and v? Justify (explain how you know) h. What's wrong with this model? Why doesn't it reflect the real physical process very well? 4