Answer Happy

(1) (H) [12.5 Marks] Calculate the molar heat of formation of nitrous acid HNO₂(aq) using the chemical equations below HNO₂ (1) (i) (ii) NH4NO₂(aq) ->N₂(g) + 2H₂O(1) * NHING:(aq) 2NH(aq)---> N₂(g) + 3H²(g) 1₂ NH₂(aq) + HNO₂(aq) --> 22(9) 22(g) + O₂(g)-> 2H₂O(1) AH* = -320.1 kJ AH* = -37.7 KJ AH* = +169.9 kJ AH"=-571.6 kJ 58.993 Predict the entropy changes for each of the equations given in part (1) Q 3(b) [10 Marks] When 88 grams CO2 (a) is heated at a constant pressure of 1.25 atm. Its temperature increases from 250 K to 277K. The molar heat capacity at constant pressure, Cpm For CO₂ is 37.11 J K mol. Using this information, calculate The heat transferred, q The changes in Enthalpy, AH The change in internal energy, AU Q3(c) [2.5 Marks] Calculate the entropy change (AS, J K mot¹) when 2.00 mol of mercury vapour at its boiling point (Tb = 356.55 °C) condenses. (in the process the temperature does not change, for mercury AHvap is + 59.3 kJ mot¹). 3.44×364