- Solution 1 2 3 4 5 Scn 0 00 M 5 M Fe Scn 4 0 000 M 4 00x105m 400x105m 100x1 M Sm 8 00x10 4 2 0 10 M 4 1 (125.65 KiB) Viewed 28 times
- Solution 1 2 3 4 5 Scn 0 00 M 5 M Fe Scn 4 0 000 M 4 00x105m 400x105m 100x1 M Sm 8 00x10 4 2 0 10 M 4 2 (100.73 KiB) Viewed 28 times
Solution # #1 #2 #3 #4 #5 [SCN] 0.00 M -5 M [Fe(SCN)²+] -4 0.000 M 4.00x105m 400x105m 100x1³m sm 8.00x10 -4 2.0×10 M -4 112x104m [Fe(SCN)2+] 1,2x10 0.41 ^ 1,6x1554 m 1,6x155-410 0.52 2,0x10 0.000 M 0.10 0.00×103m $400x1³m 0.20 6.00 -7 +2x10m 800 - 9 Absorbance 0.00 1²0X10-4 0x10m 0,60 'M
Equilibrium Constant Determination using Equation I I C E I C E I C E Fe (aq) Fe³+ (aq) + Fe (aq) 1 2 3 4 5 + + Solution # Solution #1 SCN (aq) Fe(SCN)²¹ (aq) Solution #3 SCN (aq) Fe(SCN)²¹ (aq) Solution #5 SCN (aq) Fe(SCN)²+ (aq) Standard Deviation: Keq I C E I E Fe¹¹ (aq) + Fe³¹ (aq) + Solution #2 SCN (aq) Fe(SCN)²¹ (aq) Solution #4 SCN (aq) Fe(SCN)2 (aq)