When 0.2 L of 5 M HCI is titrated with 0.4 L of 2M NaOH, how many moles is in excess of either acid or base? 0.8 moles N
Posted: Tue Jul 12, 2022 1:02 pm
When 0.2 L of 5 M HCI is titrated with 0.4 L of 2M NaOH, how many moles is in excess of either acid or base? 0.8 moles NaOH is in excess 0.2 moles HCI is in excess 0.2 moles NaOH is in excess 0.8 moles HCI is in excess 1 moles HCI is in excess