Compound A: C,H,O, B: CH.NO, Molar Mass(g/mol) 176.12 60.06 Grams CO₂ 150.00 73.33 Grams H₂O 40.88 59.93 Grams NO₂ 0.00

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Compound A: C,H,O, B: CH.NO, Molar Mass(g/mol) 176.12 60.06 Grams CO₂ 150.00 73.33 Grams H₂O 40.88 59.93 Grams NO₂ 0.00

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Compound A C H O B Ch No Molar Mass G Mol 176 12 60 06 Grams Co 150 00 73 33 Grams H O 40 88 59 93 Grams No 0 00 1
Compound A C H O B Ch No Molar Mass G Mol 176 12 60 06 Grams Co 150 00 73 33 Grams H O 40 88 59 93 Grams No 0 00 1 (14.98 KiB) Viewed 36 times
Compound A C H O B Ch No Molar Mass G Mol 176 12 60 06 Grams Co 150 00 73 33 Grams H O 40 88 59 93 Grams No 0 00 2
Compound A C H O B Ch No Molar Mass G Mol 176 12 60 06 Grams Co 150 00 73 33 Grams H O 40 88 59 93 Grams No 0 00 2 (92.93 KiB) Viewed 36 times
Compound A: C,H,O, B: CH.NO, Molar Mass(g/mol) 176.12 60.06 Grams CO₂ 150.00 73.33 Grams H₂O 40.88 59.93 Grams NO₂ 0.00 153.28 Grams OF₂ Extra Information Substances name is derived from a- scorbutus Also known as carbamide

Remember, cite all references in your post. TOPIC 2: OXIDATION/REDUCTION REACTIONS AND COMBUSTION In this topic, you will get a chance to flex your experimental muscles by calculating the empirical formula of a compound from by combusting it. Combustion analysis is a way to determine the empirical formula of a substance by burning it. This will result in the combination of each element in the substance with oxygen to form oxides of each individual element present. By analysis of the masses of the respective oxides formed, the percentages of each element in the compound can be determined and the mole ratio determined. This leads to the empirical formula. See Example 7.16, page 377 of your textbook and Figure 3, page 377. Schematic diagram illustrating the basic components of a combustion analysis device for determining carbon and hydrogen content in a samp You will identify the compound and connect it back to the first discussion, as some of these same compounds were studied there. A list of the combustion analysis for the selected compounds is given, along with the substances known elemental make up. A 100.0 g sample of each was burned. For this topic, complete the following: 1. Choose one of the compounds from the table to analyze. Remember a 100.0 gram sample was burned in the analysis. Post early to get your choice of compound as only one student may do each compound. Indicate the compound in the Subject Heading of your post. 2. Determine its empirical formula from the combustion analysis given, showing all steps and explaining your work for your fellow classmates. Determine the molecular formula from approximate molar mass provided in the table. See Section 7.5 of your textbook for example problems. 3. After determining the molecular formula, write the balanced chemical reaction for the combustion of your compound. 4. Identify your compound, which should match one of the substances used in Discussion #1: Forensic Chemistry. 5. Indicate what you found to be a challenge in this assignment about the calculations and methods to further your understanding about this method of analysis. Research your compound further and offer additional fun facts about its use or history.
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