Page 1 of 1
Part 2: A sample containing HCI is titrated with NaOH: HCI + NaOH → H₂O + NaCl A student transfers 25.00 ml. of HCI with
Posted: Tue Jul 12, 2022 12:58 pm
by answerhappygod
- Part 2 A Sample Containing Hci Is Titrated With Naoh Hci Naoh H O Nacl A Student Transfers 25 00 Ml Of Hci With 1 (37.06 KiB) Viewed 34 times
Part 2: A sample containing HCI is titrated with NaOH: HCI + NaOH → H₂O + NaCl A student transfers 25.00 ml. of HCI with a volumetric pipet to an Erlenmeyer flask, adds phenolphthalein, and titrates with NaOH (0.1000 ± 0.0004M) using a buret, to the endpoint, which requires 30.98 mL of NaOH. Volume of HC1=25.00 mL + Molarity of NaOH = 0.1000 M+ Volume NaOH-30.98 mL ± Moles NaOH => Moles HCI- Molarity HCI- Relative uncertainty (%) - Part 2b: A student transfers 25.00 mL of HCl with a graduated cylinder to an Erlenmeyer flask, adds phenolphthalein, and titrates with NaOH (0.1000 ± 0.0004M) using a buret, to the endpoint. which requires 30.9 mL of NaOH. (The student only reports value of titrant to one decimal place) Volume of HCI=25.00 mL + Molarity of NaOH = 0.1000 M + Volume NaOH = 30.9 mL + Moles NaOH = Moles HCI- Molarity HCI- Relative uncertainty (%) HH