Answer Happy

Calculate the indefinite integral. ∫[(3t+3)i+(3t+3)2j+(3t+3)−1k]dt Select the correct vector. 6(3t+3)2​i+9(3t+3)3​j+3ln∣3t+3∣​k+c 6(3t+3)2​i+9(3t+3)3​j−6(3t+3)21​k+c 2(3t+3)2​i+3(3t+3)3​j+ln∣3t+3∣k+c 3i+(18t+18)j−(3t+3)23​k+c