{x' = 3x-2y, x(0) =2 { y' = -3x-2y , y(0) = 1
Posted: Tue Jul 12, 2022 12:44 pm
{x' = 3x-2y, x(0) =2
{ y' = -3x-2y , y(0) = 1
3. (25 pts.) Solve the following system of first order differential equations using Laplace transform: Sx' = 3x - 2y, y=-3x - 2y, x(0) = 2 y(0) = 1
{ y' = -3x-2y , y(0) = 1
- X 3x 2y X 0 2 Y 3x 2y Y 0 1 1 (18.97 KiB) Viewed 38 times