Answer Happy • Question 6. (10 Marks) Prove that 1⋅1!+2⋅2!+⋯+n⋅n!=(n+1)!−1 whenever n is a non-negative integer.

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Question 6. (10 Marks) Prove that 1⋅1!+2⋅2!+⋯+n⋅n!=(n+1)!−1 whenever n is a non-negative integer.

Posted: Tue Jul 12, 2022 12:42 pm

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Question 6. (10 Marks) Prove that 1⋅1!+2⋅2!+⋯+n⋅n!=(n+1)!−1 whenever n is a non-negative integer.