Answer Happy

Match the differential equation with its direction field. y′=9(x+y)−1
Give reasons for your answer. y′=9(x+y)−1=0 on the line y=−x+1/9, and y′=−1 on the line y=−x i The slopes at each point are independent of y, so the slopes are the sarne along each line paraliel to the γ raxis. Note that for y - 9 , y ' = 0. y′=9(x2+y)−1=0 on the lines x=0 and y=0, and y′>0 for 0<x<x/9,0<y<π/9 y∗=9(x+y)−1=0 on the lines x−0 and y=9. The slopes at each peint are independent of x,​so the slopes are the same along each line parallel to the x axis. Note that fot y=9,y′=0.