A nonhomogeneous equation and a particular solution are given. Find a general solution for the equation. 0'' + 20' - 480
Posted: Tue Jul 12, 2022 12:09 pm
A nonhomogeneous equation and a particular solution are given. Find a general solution for the equation. 0'' + 20' - 480 = 3− 3t, 0p(t) = . 23 1 + -t 384 16 The general solution is 0(t) = (Do not use d, D, e, E, i, or I as arbitrary constants since these letters already have defined meanings.)