bi b2 : A= 1 -3 -4 -3 2 6 , b = 5 -1 -8 = b3
Posted: Tue Sep 07, 2021 7:37 am
Ax = b does not have a solution for all possible b, and
describe the set of all b for which Ax = b does have a
solution.
bi b2 : A= 1 -3 -4 -3 2 6 , b = 5 -1 -8 = b3